Rounding numbers in qbasic
How to round numbers to a specific number of dp

This code will show you how to round numbers in QBasic.

Firstly, a bit of background.

QBasic works with a DOUBLE data type by default. What this means is that sometimes numbers that your ordinary calculator can handle easily do not get displayed correctly in Qbasic. Here is an example:

```
CLS
PRINT 10 - 1.94
```

Now run the program, and you will see what I mean. QBasic sees the 1.94 and has a hangover when it tries to convert it to binary. The result of the code is:
1.111010100111010100101001.

Why? QB doesn't waste the time to calculate the correct values of zero (0) for the other spaces.

Here's a non-hangover result:

```
CLS
PRINT 10# - 1.94#
```

Two rounding function solutions:
```
FUNCTION round# (num AS DOUBLE, dp AS INTEGER)

'WARNING: USE "#" at the end of constant values,
'or else you will get rounding errors:
' "num = .45"  >> "num = .449999988079071
' "num = .45#" >> "num = .45"

DIM exp1 AS LONG, num2 AS LONG
exp1 = 10 ^ dp: num2 = num * exp1: round# = num2 / exp1
PRINT num
END FUNCTION
```

*OR*
```
FUNCTION round (num, dp)

'WARNING: USE "#" at the end of constant values,
'or else you will get rounding errors:
' "num = .45"  >> "num = .449999988079071
' "num = .45#" >> "num = .45"

DIM n AS DOUBLE, exp AS DOUBLE
exp = (10 ^ dp): n = num * exp
IF n >= 0 THEN
n = SGN(n) * (ABS(INT(n + .5)))
ELSE
n = SGN(n) * (ABS(INT(n - .5)))
END IF
round = n / exp
END FUNCTION
```

Example program using this function:
```
num# = 12.3892#
dp = 2
decplaces = round(num#, dp)
```

credit: Oracle, Moneo, Agamemnus

RoundingNumbers - page last edited 2004-03-27 11:19:42 by 172.151.106.223 (home) (edit)
Blast WIKI - by RoboticBoy - edited and tweaked for our evil purposes by Hexadecimal Disaster